X^3 + 4x^2 – 11x – 30 = (x+2) (x-3) (x+5)=0

Question

X^3 + 4x^2 – 11x – 30 = (x+2) (x-3) (x+5)=0

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Neala 5 years 2021-09-05T01:19:31+00:00 1 Answers 22 views 0

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  1. Edana
    0
    2021-09-05T01:20:52+00:00
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    Answer:

    STEP   1

    Equation at the end of step 1

     (((x3) –  22×2) –  11x) +  30

    STEP  2

    Checking for a perfect cube

    2.1    x3-4×2-11x+30  is not a perfect cube

    Trying to factor by pulling out :

    2.2      Factoring:  x3-4×2-11x+30  

    Thoughtfully split the expression at hand into groups, each group having two terms :

    Group 1:  -11x+30  

    Group 2:  x3-4×2  

    Pull out from each group separately :

    Group 1:   (-11x+30) • (1) = (11x-30) • (-1)

    Group 2:   (x-4) • (x2)

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )