rút gọn 3.(4^2+1).(4^4+1).(4^8+1).(4^16+1).(4^32+1) Question rút gọn 3.(4^2+1).(4^4+1).(4^8+1).(4^16+1).(4^32+1) in progress 0 Môn Toán Delwyn 4 years 2020-10-30T13:01:01+00:00 2020-10-30T13:01:01+00:00 2 Answers 95 views 0
Answers ( )
Đáp án:
Giải thích các bước giải:
Đặt `A=3.(4^2+1).(4^4+1).(4^8+1).(4^16+1).(4^32+1)`
`=>5A=(4-1)(4+1).(4^2+1)(4^4+1).(4^8+1).(4^16+1).(4^32+1)`
`=>5A=(4^2-1)(4^2+1)(4^4+1).(4^8+1).(4^16+1).(4^32+1)`
`=>5A=(4^4-1)(4^4+1).(4^8+1).(4^16+1).(4^32+1)`
`=>5A=(4^8-1)(4^8+1)(4^16+1).(4^32+1)`
`=>5A=(4^16-1)(4^16+1)(4^32+1)`
`=>5A=(4^32-1)(4^32+1)`
`=>5A=4^64-1`
`=>A=(4^64-1)/5`
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Đáp án:
Đặt ` A = 3.(4^2+1).(4^4+1).(4^8+1).(4^{16}+1).(4^{32}+1)`
`=> 5A = 15(4^2+1).(4^4+1).(4^8+1).(4^{16}+1).(4^{32}+1)`
`=> 5A = (4^2 – 1)(4^2+1).(4^4+1).(4^8+1).(4^{16}+1).(4^{32}+1)`
`=> 5A = (4^4 – 1)(4^4+1).(4^8+1).(4^{16}+1).(4^{32}+1)`
`=> 5A = (4^8 – 1)(4^8+1).(4^{16}+1).(4^{32}+1)`
`=> 5A = (4^{16} – 1).(4^{16}+1).(4^{32}+1)`
`=> 5A = (4^{32} – 1)(4^{32} + 1)`
`=> 5A = 4^{64} – 1`
`=> A = (4^{64} – 1)/5`
Giải thích các bước giải: