Giải hộ em với ạ, em cảm ơn.

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Giải hộ em với ạ, em cảm ơn.
giai-ho-em-voi-a-em-cam-on

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Gerda 5 years 2021-05-23T17:13:34+00:00 2 Answers 27 views 0

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  1. mocmien2
    0
    2021-05-23T17:15:21+00:00
    Reply

    Đáp án:

     

    Giải thích các bước giải:

    a)

    `19/(2^2 . 3^2 . 5^4)=(19 . 2^2)/(2^4 . 3^2 . 5^4)=76/(2^4 . 3^2 . 5^4)`

    `11/(2^4 . 3 . 5^3)=(11 . 3 . 5)/(2^4 . 3^2 . 5^4)=165/(2^4 . 3^2 . 5^4)`

    Vì `76<165 to 76/(2^4 . 3^2 . 5^4)<165/(2^4 . 3^2 . 5^4)`

    hay `19/(2^2 . 3^2 . 5^4)<11/(2^4 . 3 . 5^3)`

    b)

    `13/(3 . 7^2 . 11)=(13 . 3 . 13)/(3^2 . 7^2 . 11 . 13)=507/(3^2 . 7^2 . 11 . 13)`

    `17/(3^2 . 7 . 13)=(17 . 7 . 11)/(3^2 . 7^2 . 11 . 13)=1309/(3^2 . 7^2 . 11 . 13)`

    Vì `507<1309 to 507/(3^2 . 7^2 . 11 . 13)<1309/(3^2 . 7^2 . 11 . 13)`

    hay `13/(3 . 7^2 . 11)<17/(3^2 . 7 . 13)`

  2. dangkhoa
    0
    2021-05-23T17:15:30+00:00
    Reply

    Giải thích các bước giải:

     a) Ta có:

    $\begin{array}{l}
    \dfrac{{19}}{{{2^2}{{.3}^2}{{.5}^4}}} = \dfrac{{{{19.2}^2}}}{{{2^4}{{.3}^2}{{.5}^4}}} = \dfrac{{76}}{{{2^4}{{.3}^2}{{.5}^4}}}\\
    \dfrac{{11}}{{{2^4}{{.3.5}^3}}} = \dfrac{{11.3.5}}{{{2^4}{{.3}^2}{{.5}^4}}} = \dfrac{{165}}{{{2^4}{{.3}^2}{{.5}^4}}}
    \end{array}$

    b) Ta có:

    $\begin{array}{l}
    \dfrac{{13}}{{{{3.7}^2}.11}} = \dfrac{{13.3.13}}{{{3^2}{{.7}^2}.11.13}} = \dfrac{{507}}{{{3^2}{{.7}^2}.11.13}}\\
    \dfrac{{17}}{{{3^2}.7.13}} = \dfrac{{17.7.11}}{{{3^2}{{.7}^2}.11.13}} = \dfrac{{1309}}{{{3^2}{{.7}^2}.11.13}}
    \end{array}$

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