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Đáp án:
`a)` `4/9`
`b)` `5`
`c)` `2013/6039`
Giải thích các bước giải:
`a)` `(-3)/4+3/7+(-1)/4+4/9+4/7`
`=((-3)/4+(-1)/4)+(3/7+4/7)+4/9`
`=(-1)+1+4/9`
`=0+4/9`
`=4/9`
________________________
`b)` `(-7)/9*4/11+(-7)/9*7/11+5(7)/9`
`=(-7)/9*4/11+(-7)/9*7/11+52/9`
`=(-7)/9*(4/11+7/11)+52/9`
`=(-7)/9+52/9`
`=5`
________________________
`c)` `(21/31+2013/6039)-(44/53-10/31)-9/53`
`=21/31+2013/6039-44/53+10/31-9/53`
`=(21/31+10/31)+2013/6039-(44/53+9/53)`
`=1+2013/6039-1`
`=1-1+2013/6039`
`=2013/6039`
a) $\frac{-3}{4}$ + $\frac{3}{7}$ + $\frac{-1}{4}$ + $\frac{4}{7}$
=($\frac{-3}{4}$ + $\frac{-1}{4}$ ) + ( $\frac{3}{7}$ + $\frac{4}{7}$ ) + $\frac{4}{9}$
= $\frac{-4}{4}$ + $\frac{7}{7}$ + $\frac{4}{9}$
= -1 + 1 + $\frac{4}{9}$
= 0 + $\frac{4}{9}$ = $\frac{4}{9}$
b) $\frac{-7}{9}$ . $\frac{4}{11}$ + $\frac{-7}{9}$ . $\frac{7}{11}$ + 5$\frac{7}{9}$
= $\frac{-7}{9}$ . ( $\frac{4}{11}$ + $\frac{7}{11}$ ) + 5$\frac{7}{9}$
= $\frac{-7}{9}$ . $\frac{11}{11}$ + 5$\frac{7}{9}$
= $\frac{-7}{9}$ .1 + 5$\frac{7}{9}$
= $\frac{-7}{9}$ + 5 + $\frac{7}{9}$
= ( $\frac{-7}{9}$ + $\frac{7}{9}$ ) + 5
= 0+ 5 = 5
c) ($\frac{21}{31}$ + $\frac{2013}{6039}$ ) – ($\frac{44}{53}$ – $\frac{10}{31}$ ) – $\frac{9}{53}$
= $\frac{21}{31}$ + $\frac{1}{3}$ – $\frac{44}{53}$ + $\frac{10}{31}$ – $\frac{9}{53}$
= $\frac{21}{31}$ + $\frac{1}{3}$ + $\frac{-44}{53}$ + $\frac{10}{31}$ + $\frac{-9}{53}$
= ( $\frac{21}{31}$ + $\frac{10}{31}$ ) + ( $\frac{-44}{53}$ + $\frac{-9}{53}$ ) + $\frac{1}{3}$
= 1 + (-1) + $\frac{1}{3}$
= 0 + $\frac{1}{3}$ = $\frac{1}{3}$