Tính đạo hàm giúp mình với

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Tính đạo hàm giúp mình với
tinh-dao-ham-giup-minh-voi

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Nick 5 years 2021-05-21T02:15:46+00:00 2 Answers 14 views 0

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  1. Cherry
    0
    2021-05-21T02:16:49+00:00
    Reply

    Đáp án:

    $y’ = \dfrac{4\tan\left(2x -\dfrac{\pi}{4}\right)}{\cos^2\left(2x -\dfrac{\pi}{4}\right)}$

    Giải thích các bước giải:

    $\quad y =\tan^2\left(2x -\dfrac{\pi}{4}\right)$

    $\to y ‘ =2\tan\left(2x -\dfrac{\pi}{4}\right).\left[\tan\left(2x -\dfrac{\pi}{4}\right)\right]’$

    $\to y’ = 2\tan\left(2x -\dfrac{\pi}{4}\right)\cdot\dfrac{\left(2x -\dfrac{\pi}{4}\right)’}{\cos^2\left(2x -\dfrac{\pi}{4}\right)}$

    $\to y’ = \dfrac{4\tan\left(2x -\dfrac{\pi}{4}\right)}{\cos^2\left(2x -\dfrac{\pi}{4}\right)}$

  2. King
    0
    2021-05-21T02:16:50+00:00
    Reply

    $y=\tan^2\Big(2x-\dfrac{\pi}{4}\Big)$

    $y’=2\tan\Big(2x-\dfrac{\pi}{4}\Big).\Big[\tan\Big(2x-\dfrac{\pi}{4}\Big)]’$

    $=2\tan\Big(2x-\dfrac{\pi}{4}\Big).\dfrac{\Big(2x-\dfrac{\pi}{4}\Big)’ }{\cos^2\Big(2x-\dfrac{\pi}{4}\Big)}$

    $=\dfrac{4\tan\Big(2x-\dfrac{\pi}{4}\Big) }{\cos^2\Big(2x-\dfrac{\pi}{4}\Big)}$

    $=\dfrac{4\sin\Big(2x-\dfrac{\pi}{4}\Big)}{ \cos^3\Big(2x-\dfrac{\pi}{4}\Big)}$

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