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y = (x2 – 2x + 1) y = (x – 1)(x – 1) Prove that the following functions are equivalent through algebraic and numerical proof
Question
y = (x2 – 2x + 1)
y = (x – 1)(x – 1)
Prove that the following functions are equivalent through algebraic and numerical proof
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Mathematics
5 years
2021-09-05T00:53:41+00:00
2021-09-05T00:53:41+00:00 2 Answers
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Answers ( )
y = (x^2 – 2x + 1)
y = (x – 1)(x – 1)
Algebraic Proof
FOIL y = (x – 1)(x – 1)
y = (x – 1) (x -1 ) = x^2 -2x + 1
Done.
Numeric Proof
Let x = 1
y = x^2 – 2x + 1
y = (1)^2 – 2(1) + 1
y = 1 – 2 + 1
y = 2 + 2
y = 0
Let x be 1 again.
y = (x – 1)(x – 1)
y = (1 – 1)(1 – 1)
y = 0
There you have it. Both equations are the same.
Answer:
see below
Step-by-step explanation:
y = (x² – 2x + 1)
y = (x – 1)(x – 1)
First, recognize that the first equation is fully simplified/expanded already.
Now, we should solve for the second equation.
FOIL the expressions: first–outer–inner–last
(x – 1)(x – 1)
F: x²
O: -x
I: -x
L: 1
Combine these terms.
x² – x – x + 1
x² – 2x + 1
Notice that this equation is identical to our first equation. Therefore, the functions are equivalent.
Hope this helps!