If the function h is defined by h(x)=x^{2}-3x+5,then h(2x+1)=

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If the function h is defined by h(x)=x^{2}-3x+5,then h(2x+1)=

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Phúc Điền 4 years 2021-07-30T10:51:12+00:00 1 Answers 24 views 0

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  1. thanhcong
    0
    2021-07-30T10:52:42+00:00
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    Given:

    The function is:

    h(x)=x^2-3x+5

    To find:

    The value of h(2x+1).

    Solution:

    We have,

    h(x)=x^2-3x+5

    Putting x=2x+1, we get

    h(2x+1)=(2x+1)^2-3(2x+1)+5

    h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5

    h(2x+1)=4x^2+4x+1-6x-3+5

    On combining like terms, we get

    h(2x+1)=4x^2+(4x-6x)+(1-3+5)

    h(2x+1)=4x^2-2x+3

    Therefore, the required function is h(2x+1)=4x^2-2x+3.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )