Construct a quadrilateral ABCD , Where AB- 6cm , CD- 6.5cm , LL- 70°, LA- 95°​

Question

Construct a quadrilateral ABCD , Where AB- 6cm , CD- 6.5cm , LL- 70°, LA- 95°​

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Hồng Cúc 4 years 2021-07-29T06:23:43+00:00 1 Answers 17 views 0

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  1. Ben
    0
    2021-07-29T06:25:15+00:00
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    Answer:

    Solution:

    Given : A quadrilateral A B CD, in which, AB=5  cm, BC = 6 cm, CD =6.5 cm , angle B= 105° and angle C = 75

    Steps of construction

    (1) Draw a line segment B C of length 6 cm.

    (2) At Point B and C , with the help of Compass draw angle of  105° and 75° respectively.Name the rays as C M and B Z respectively.

    105°→Draw an angle of 120° and 90° and draw angle bisector between 90° and 120°.

    75°→Draw angle bisector of 60° and 90°.

    (3) From C , mark an arc at a distance of 6.5 cm on ray CM.You will get point D.

    (4) From B , mark an arc at a distance of 5 cm on ray B Z.You will get point A.

    (5) Join A and D.

    This is required trapezoid A B CD.

    here, AB ║CD→→∠B+∠C=180°[If sum of interior angles on the same side of transversal is supplementary then lines are parallel.]

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