tính: 2x^4-3x³-7x²+6x+8

Question

tính: 2x^4-3x³-7x²+6x+8

in progress 0
Nem 5 years 2020-10-27T07:43:09+00:00 2 Answers 92 views 0

Answers ( )

  1. Sigrid
    0
    2020-10-27T07:44:39+00:00
    Reply

    $2x^4-3x^3-7x^2+6x+8$

    $=2x^4-4x^3+x^3-2x^2-5x^2+10x-4x+8$

    $=2x^3(x-2)+x^2(x-2)-5x(x-2)-4(x-2)$

    $=(2x^3+x^2-5x-4)(x-2)$

  2. Adela
    0
    2020-10-27T07:45:01+00:00
    Reply

    Đáp án:

     `(x-2)(x+1)(2x^2-x-4)`

    Giải thích các bước giải:

     `2x^4-3x^3-7x^2+6x+8`

    `=2x^4-4x^3+x^3-2x^2-5x^2+10x-4x+8`

    `=2x^3(x-2)+x^2(x-2)-5x(x-2)-4(x-2)`

    `=(x-2)(2x^3+x^2-5x-4)`

    `=(x-2)(2x^3+2x^2-x^2-x-4x-4)`

    `=(x-2)[2x^2(x+1)-x(x+1)-4(x+1)]`

    `=(x-2)(x+1)(2x^2-x-4)`

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )