Will Mark Branliest for Best Answer!! Plz Help! A juggler throws a ball from an initial height of 4 feet with an initial velocit

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Will Mark Branliest for Best Answer!! Plz Help!

A juggler throws a ball from an initial height of 4 feet with an initial velocity of 30 feet per second. The height h (in feet) of the ball can be modeled by h=−16t2+vt+s where t is the time (in seconds) the ball has been in the air. v is the initial velocity and s is the initial height.

Write an equation that gives the height (in feet of the ball since it left the juggler’s hand. )

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Khánh Gia 3 years 2021-07-16T19:35:25+00:00 1 Answers 5 views 0

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    2021-07-16T19:37:08+00:00

    Answer:h=16+2+vt +s

    Step-by-step explanation:

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )