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Cho $f(x)$ = $ax^{3}$ + $4x(x^{2}-1)+8$ và $g(x)$ = $x^{3}$ + $4x(bx+1)$ + $c$ – $3$ trong đó $a$, $b$, $c$ là hằng số. Xác định $a$, $b$, $c$ để $f(
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$f(x)=ax^3+4x(x^2-1)+8\\ =ax^3+4x^3-4x+8\\ =(a+4)x^3-4x+8\\ g(x)=x^3+4x(bx-1)+c-3\\ =x^3+4bx^2-4x+c-3\\ f(x)=g(x)\\ \Rightarrow \left\{\begin{array}{l} a+4=1\\ 4b=0 \\ c-3=8\end{array} \right.\\ \Leftrightarrow \left\{\begin{array}{l} a=-3\\ b=0 \\ c=11\end{array} \right.$