tính tổng C= 1/3 +1/3^2+1/3^3+…+1/3^10 dấu/ là phân số nha các bạn Question tính tổng C= 1/3 +1/3^2+1/3^3+…+1/3^10 dấu/ là phân số nha các bạn in progress 0 Môn Toán Calantha 6 years 2020-10-25T07:41:59+00:00 2020-10-25T07:41:59+00:00 2 Answers 93 views 0
Answers ( )
Giải thích các bước giải:
`C= 1/3 +1/3^2+1/3^3+…+1/3^10 `
`=>3C= 1 +1/3+1/3^2+…+1/3^9`
`=>3C-C=(1 +1/3+1/3^2+…+1/3^9)-( 1/3 +1/3^2+1/3^3+…+1/3^10)`
`=>2C=1-1/3^10=(3^10-1)/3^10`
`=>C=(3^10-1)/2.3^10`
Đáp án:
`C= 1/3 +1/3^2+1/3^3+…+1/3^10`
`=> 3C = 1 + 1/3 + 1/3^2 + … + 1/3^9`
`=> 3C – C = (1 + 1/3 + 1/3^2 + … + 1/3^9) – ( 1/3 +1/3^2+1/3^3+…+1/3^10)`
`=> 2C = 1 + 1/3 + 1/3^2 + … + 1/3^9 – 1/3 -1/3^2-1/3^3-…-1/3^10`
`=> 2C = 1 – 1/3^10`
`=> C = (1 – 1/3^10)/2`
` Go od luck !`