Find the Relative Change in the values of the function f(x) = x3 + 2 between x = 1 and x = 2.5 Enter your answer accurate to three digits to

Question

Find the Relative Change in the values of the function f(x) = x3 + 2 between x = 1 and x = 2.5 Enter your answer accurate to three digits to the right of the decimal point.

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Thu Nguyệt 3 years 2021-08-12T11:46:21+00:00 1 Answers 6 views 0

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    2021-08-12T11:47:21+00:00

    Answer:

    9.750

    Step-by-step explanation:

    formula for average rate of change is ;

    f(b)- f(a)/b- a

    here a = 1 and b = 2.5

    f(b) = (2.5)^3 + 2 = 17.625

    f(a) = 1^3+ 2 = 3

    using the formula above, we have it that

    (17.625-3)/2.5-1 = 9.750

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )