Solve 2x-5/x-2 ≤ 1 please answer fast ​

Question

Solve 2x-5/x-2 ≤ 1

please answer fast ​

in progress 0
RuslanHeatt 3 years 2021-09-02T06:54:56+00:00 2 Answers 4 views 0

Answers ( )

    0
    2021-09-02T06:56:25+00:00

    Answer:

    x<=-3

    Step-by-step explanation:

    2x-5/x-2 <= 1

    Multiply both sides by x-2

    2x-5<=x-2 (anything times 1 is that number.)

    add 5 to both sides

    2x<=x-3

    subtract x from both sides

    x<=-3

    0
    2021-09-02T06:56:50+00:00

    Answer:

    Step-by-step explanation:

    \frac{2x-5}{x-2} \leq 1\\case ~1. both ~numerator~and~denominator \geq 0\\x\neq 2\\2x-5\leq x-2\\x\leq 3\\so~0\leq x<2U2<x\leq 3\\case~2.\\both~numerator~and~denominator<0\\2x-5\geq x-2\\x>3\\which~is~rejected~as~it~gives~both~2x-5~and ~x-2>0

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )