Question 3 Determine the leg lengths between the two points: (6, -3) and (-2,4). what the shortest leg length? and what is the th

Question

Question 3 Determine the leg lengths between the two points: (6, -3) and (-2,4).
what the shortest leg length?
and what is the the longest leg length?
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Helga 5 years 2021-09-01T15:49:53+00:00 1 Answers 10 views 0

Answers ( )

  1. thienthanh
    0
    2021-09-01T15:51:31+00:00
    Reply

    Answer:

    9

    Step-by-step explanation:

    →You can use the Pythagorean Theorem to solve this, by plugging in the numbers, like so:

    \begin{gathered}a^2+b^2=c^2\\x^2+(x-3)^2=(x+3)^2\end{gathered}

    a

    2

    +b

    2

    =c

    2

    x

    2

    +(x−3)

    2

    =(x+3)

    2

    x^2+x^2-6x+9=x^2+6x+9x

    2

    +x

    2

    −6x+9=x

    2

    +6x+9

    →Subtract x^2-6x+9x

    2

    −6x+9 from both sides:

    x^2 = 12xx

    2

    =12x

    →Subtract 12x from both sides:

    x^2 -12x=0x

    2

    −12x=0

    →Factor out x:

    x(x-12)=0x(x−12)=0

    →Separate, set = to 0, and solve:

    \begin{gathered}x = 0\\x -12=0\end{gathered}

    x=0

    x−12=0

    → Add 12 to both sides: x = 12x=12

    →So we have 0 and 12, as our answers. However, we cannot have 0 as a side length, since this would not be possible.

    →All we need to do is take 12, and plug it into the equation for the shortest leg.

    \begin{gathered}x – 3=?\\12-3=9\end{gathered}

    x−3=?

    12−3=9

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )