What is the equation of the line that is parallel to the given line and passes through the point (–2, 2)? Given line: y=1/5x-3

Question

What is the equation of the line that is parallel to the given line and passes through the point (–2, 2)?
Given line: y=1/5x-3

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MichaelMet 4 years 2021-08-23T22:19:55+00:00 1 Answers 17 views 0

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  1. Tryphena
    0
    2021-08-23T22:21:03+00:00
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    Answer:

    y = 1/5 x + 12/5

    Step-by-step explanation:

    We are looking for the equation of a line.

    We satart with the slope-intercept form of the equation of a line.

    y = mx + b

    We need to find m, the slope, and b, the y-intercept.

    The given line is y = 1/5 x – 3.

    Its slope is 1/5.

    Parallel lines have equal slopes, so the slope we need is also 1/5.

    Now we have for our line

    y = 1/5 x + b

    Now we find b.

    We are given a point on the line, (-2, 2). Using the slope we already know, plug in (-2, 2) in the equation and solve for b.

    2 = 1/5 * (-2) + b

    10 = -2 + 5b

    12 = 5b

    b = 12/5

    Now that we know the y-intercept, we can write the equation of the line.

    y = 1/5 x + 12/5

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )