Isabella had a big bag of sweets,she ate two fifth of them on Monday,two fifth of those remaining on Tuesday,and two thirds of what remainin

Question

Isabella had a big bag of sweets,she ate two fifth of them on Monday,two fifth of those remaining on Tuesday,and two thirds of what remaining on Wednesday.She then had 12 sweets.How many were in the bag originally?

in progress 0
Ngọc Khuê 4 years 2021-08-20T09:40:01+00:00 1 Answers 24 views 0

Answers ( )

  1. Gerda
    0
    2021-08-20T09:41:25+00:00
    Reply

    Answer:

    100 sweets

    Step-by-step explanation:

    Let initial number of sweet = x

    Monday :

    2/5 of x = 2x/5

    Number left = x – 2x/5 = 3x/5

    Tuesday :

    2/5 of remaining = 2/5 * 3x/5 = 6x/25

    Number left = 3x/5 – 6/25 = 9x/25

    Wednesday :

    2/3 of remaining = 2/3 * 9x/25 = 18x/75

    Number left = 9x/25 – 18x/75 = 9x / 75

    9x/75 corresponds to 12

    9x/75 = 12

    Cross multiply :

    9x = 12 * 75

    9x = 900

    x = 900 / 9

    x = 100 sweets

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )