Walter used the iterative process to determine that √13 is between 3.61 and 3.62. Analyze Walter’s estimation. Is he correct? If not, what w

Question

Walter used the iterative process to determine that √13 is between 3.61 and 3.62. Analyze Walter’s estimation. Is he correct? If not, what was his mistake?

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Thiên Ân 4 years 2021-08-10T06:33:16+00:00 2 Answers 126 views 0

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  1. Neala
    0
    2021-08-10T06:34:20+00:00
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    Question options:

    A. Yes, Walter is correct.

    B. No 3.612 is less than 13.

    C. No, both 3.612 and 3.622 are greater than

    D. No, both 3.612 and 3.622 are less than 13

    Answer:

    C. No, both 3.612 and 3.622 are greater than the square root of 13

    Explanation:

    13 is a prime number and must have a decimal number as its square root and so the square root should be between √9 and √16

    Using the Newton Raphson method to estimate the square root of 13 with the formula: ai +1= ai²+n/2ai

    We get square root of 13 = 3.6055512

    This is the same result we get using a calculator to calculate square root of 13= 3.6055512

    So yes Walter is not correct

  2. nguyetanh
    0
    2021-08-10T06:35:03+00:00
    Reply

    Answer:

    yes he is correct

    Step-by-step explanation:

    Yes, Walter is correct.

    No, 3.612 is less than 13.

    No, both 3.612 and 3.622 are greater than 13.

    No, both 3.612 and 3.622 are less than 13

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