Show A and Show B are two of the most popular television shows of all time. The number of episodes of each show are consecutive even integer

Question

Show A and Show B are two of the most popular television shows of all time. The number of episodes of each show are consecutive even integers whose sum is 570. If there are more episodes of Show A, how many episodes of each were there?

in progress 0
Thông Đạt 5 years 2021-08-10T00:27:20+00:00 1 Answers 20 views 0

Answers ( )

    0
    2021-08-10T00:29:00+00:00

    Answer:

    A = 286 episodes

    B = 284 episodes

    Step-by-step explanation:

    Let n = the \text{number of episodes} of show B

        n + 2 = the \text{number of episodes} of show A

    Therefore, according to the question,

    The sum of the number of the episodes of each show are consecutive even integers  = 570

    Therefore,

    n + n + 2 = 570

    2n + 2 = 570

    2n = 568

    n = 284

    Therefore, the number of episodes for B = 284

    The number of episodes for A = n + 2 = 284 + 2

                                                                  = 286

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )