In the diagram, WZ=StartRoot 26 EndRoot. On a coordinate plane, parallelogram W X Y Z is shown. Point W is at (negative 2, 4), p

Question

In the diagram, WZ=StartRoot 26 EndRoot.

On a coordinate plane, parallelogram W X Y Z is shown. Point W is at (negative 2, 4), point X is at (2, 4), point Y is at (1, negative 1), and point Z is at (negative 3, negative 1).

What is the perimeter of parallelogram WXYZ?

units
units
units
units

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Nem 4 years 2021-08-03T00:37:15+00:00 1 Answers 179 views 0

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  1. Doris
    0
    2021-08-03T00:38:37+00:00
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    Answer:

    P = 8 + 2\sqrt{26}

    Step-by-step explanation:

    Given

    W = (-2, 4)

    X = (2, 4)

    Y = (1, -1)

    Z = (-3,-1)

    Required

    The perimeter

    First, calculate the distance between each point using:

    d = \sqrt{(x_1 - x_2)^2 + (y_1 -y_2)^2

    So, we have:

    WX = \sqrt{(-2- 2)^2 + (4-4)^2 } =4

    XY = \sqrt{(2- 1)^2 + (4--1)^2 } =\sqrt{26}

    YZ = \sqrt{(1- -3)^2 + (-1--1)^2 } =4

    ZW = \sqrt{(-3--2)^2 + (-1-4)^2 } =\sqrt{26}

    So, the perimeter (P) is:

    P = 4 + \sqrt{26} + 4 + \sqrt{26}

    P = 8 + 2\sqrt{26}

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