The surface area of a roof with dimensions of 40 feet long by 28 feet wide is how many times the surface area of a floor where the dimension

Question

The surface area of a roof with dimensions of 40 feet long by 28 feet wide is how many times the surface area of a floor where the dimensions are 16 feet long by 7 feet wide?

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Latifah 4 years 2021-08-02T07:32:19+00:00 1 Answers 17 views 0

Answers ( )

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    2021-08-02T07:33:50+00:00

    Answer:

    10 times

    Step-by-step explanation:

    Multiply 40 by 28

    1120

    Multiply 16 by 7

    112

    Divide the two numbers

    You get 10

    Hope this helps!

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