The center of the circle is located (3’8), and the circle has a radius that is 5 units long. What is the general form of the equation for th

Question

The center of the circle is located (3’8), and the circle has a radius that is 5 units long. What is the general form of the equation for the circle

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Farah 4 years 2021-07-29T05:42:30+00:00 1 Answers 84 views 0

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  1. Sigrid
    0
    2021-07-29T05:43:47+00:00
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    9514 1404 393

    Answer:

      x² +y² -6x -16y +48 = 0

    Step-by-step explanation:

    Given:

    • circle center: (3, 8)
    • circle radius: 5

    Find:

      general form equation for the circle

    Solution;

    The standard form equation for the circle is …

      (x -h)² +(y -k)² = r² . . . . . circle with radius r centered at (h, k)

      (x -3)² +(y -8)² = 5²

    Subtracting 25 and expanding this will give the general form.

      x² -6x +9 +y² -16y +64 -25 = 0

      x² +y² -6x -16y +48 = 0

    _____

    Additional comment

    “General form” of an equation is usually the form f(x,y) = 0, where f(x, y) is written in “standard form,” with terms in lexicographical order and decreasing degree.

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