What is the following sum? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0StartRoot x^2y^3 EndRoot +2 StartRoot x^3y^4

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What is the following sum? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0StartRoot x^2y^3 EndRoot +2 StartRoot x^3y^4 EndRoot +xy StartRoot y EndRoot

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Đan Thu 5 years 2021-07-26T00:44:41+00:00 1 Answers 23 views 0

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  1. thienan
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    2021-07-26T00:46:06+00:00
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    Answer:

    Assume x greater-than-or- equal-to 0 and y … 0 StartRoot x squared y cubed EndRoot + 2 StartRoot x cubed y Superscript 4 Baseline EndRoot + x y StartRoot y EndRoot.

    Step-by-step explanation:

    Option (b) is correct.

    The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy is  2xy\sqrt{y}+2xy^2\sqrt{x}2xyy+2xy2x

    Step-by-step explanation:

    Given:Expression \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy

    We have to find the sum of the given expression and choose the correct from the given options.

    Consider the given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy .

    \sqrt{x^2y^3}x2y3 can be written as \sqrt{x^2y^2y}=xy\sqrt{y}x2y2y=xyy

    Also, 2\sqrt{x^3y^4}2x3y4 can be written as 2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}2x3y4=2x2x(y2)2=2xy2x

    Now, the given expression becomes,

    x2y3+2x3y4+xyy

    =xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}=xyy+2xy2x+xyy .

    Now, adding like term, terms having same variable with same degree.

    =2xy\sqrt{y}+2xy^2\sqrt{x}=2xyy+2xy2x .

    Thus, The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy is  2xy\sqrt{y}+2xy^2\sqrt{x}2xyy+2xy2x

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