The electric field everywhere on the surface of a thin, spherical shell of radius 0.725 m is of magnitude 899 N/C and points radially toward

Question

The electric field everywhere on the surface of a thin, spherical shell of radius 0.725 m is of magnitude 899 N/C and points radially toward the center of the sphere.What is the net charge within the sphere’s surface

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Hải Đăng 3 years 2021-09-05T16:46:22+00:00 1 Answers 7 views 0

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  1. thuhuong
    0
    2021-09-05T16:48:04+00:00
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    Answer:

    Q = -52.56 nC

    Explanation:

    The electric field outside a spherical shell is given by

    E = \frac{k*Q}{r^{2} }

    where:

    Q is the net  charge

    r is the radius of the spherical shell and E is the electric field magnitude.

    Given:

    r = 0.725 m

    since the field points radially toward the center of the sphere, E = -899 N/C.

    k is a constant with a value = 8.99 x 109 Nm²/C².

    ∴-899 = \frac{8.99*10^{9} *Q}{0.725^{2} }

    Q = \frac{-899*0.725^{2} }{8.99*10^{9} }=-5.256*10^{-8}

    Q = -52.56 nC

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