A bullet is accelerated down the barrel of a gun by hot gases produced in the combustion of gun powder. What is the average force (in N) exe

Question

A bullet is accelerated down the barrel of a gun by hot gases produced in the combustion of gun powder. What is the average force (in N) exerted on a 0.0500 kg bullet to accelerate it to a speed of 625 m/s in a time of 1.10 ms (milliseconds)

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Đan Thu 5 years 2021-08-31T20:52:53+00:00 1 Answers 32 views 0

Answers ( )

  1. linhdan
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    2021-08-31T20:54:08+00:00
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    Answer:

    28409.1 N

    Explanation:

    Force: This can be defined as the product of mass and acceleration. The S.I unit of force is Newton(N).

    From the question,

    F = ma……………………….Equation 1

    Where F = force exerted on the bullet, m = mass of the bullet, a = acceleration of the bullet.

    But,

    a = v/t……………………….. Equation 2

    Where v = velocity,t = time.

    Substitute equation 2 into equation 1

    F = m(v/t)……………………. Equation 3

    Given: m = 0.05 kg, v = 625 m/s, t = 1.1 ms = 0.0011 s.

    Substitute into equation 3

    F = 0.05(625)/0.0011

    F = 28409.1 N

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