Two straight wires separated by a very small distance run parallel to each other, one carrying a current of 3.0 A to the right and the other

Question

Two straight wires separated by a very small distance run parallel to each other, one carrying a current of 3.0 A to the right and the other carrying a current of 6.8 A to the left. Give the approximate value for the magnitude of the magnetic field a large distance r from both wires.

B=……………………(1/r) T.m

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Diễm Kiều 5 years 2021-08-29T09:44:23+00:00 1 Answers 39 views 0

Answers ( )

  1. mocmien2
    0
    2021-08-29T09:45:26+00:00
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    Answer:

    Explanation:

    I1 = 3 A right

    I2 = 6.8 A left

    Let the distance is r from both the wires on the same side.

    The formula for the magnetic field is given by

    B =\frac{\mu _{0}}{4\pi }\frac{2i}{r}

    As the direction of current in both the wires is opposite to each other

    so the net magnetic field is

    B = B2 – B1

    B =\frac{\mu _{0}}{4\pi }\frac{2i_{2}}{r}-\frac{\mu _{0}}{4\pi }\frac{2i_{1}}{r}

    B =\frac{\mu _{0}}{4\pi }\frac{2\times 6.8}{r}-\frac{\mu _{0}}{4\pi }\frac{2\times 3}{r}

    B =\frac{\mu _{0}}{4\pi }\frac{7.6}{r}

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