A neon gas tube has Von = 60.0 V and Voff = 30.0 V . What resistor value should you choose to go with a 20.0 μF capacitor and a 120 V batter

Question

A neon gas tube has Von = 60.0 V and Voff = 30.0 V . What resistor value should you choose to go with a 20.0 μF capacitor and a 120 V battery to make a 30.0 Hz oscillator?

in progress 0
bonexptip 5 years 2021-08-28T21:04:54+00:00 1 Answers 7 views 0

Answers ( )

  1. thongdat2
    0
    2021-08-28T21:06:04+00:00
    Reply

    Answer:

    Therefore,

    The resistor value , R is 9.4 kΩ.

    Explanation:

    Given:

    A neon gas tube has

    Von = 60.0 V and

    Voff = 30.0 V

    Capacitor, C =  20.0 μF

    Battery , E = 120  V

    Frequency = f = 30 hz

    Time\ period =T=\dfrac{1}{f}=\dfrac{1}{30}=0.033\ s

    To Find:

    Resistor , R =?

    Solution:

    Time period of the wave will be only the charging time of the capacitor,the capacitor will be charged to Von from initial voltage Voff  is given by,

    T=RC\ln(\dfrac{E-V_{off}}{E-V_{on}})

    Where,

    R = Resistance

    C =Capacitance

    E = Battery in volts

    ln = natural Log (Sign)

    Substituting the values we get

    0.033=R\times 20\times 10^{-6}\ln(\dfrac{120-30}{120-60})

    0.033=R\times 20\times 10^{-6}\ln(1.5)

    0.033=R\times 20\times 10^{-6}\times 0.176

    R=9.375\times 10^{3}=9.4\ k\Omega

    Therefore,

    The resistor value , R is 9.4 kΩ.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )