Heat is transferred at a rate of 2 kW from a hot reservoir at 800 K to a cold reservoir at 300 K. Calculate the rate at which the entropy of

Question

Heat is transferred at a rate of 2 kW from a hot reservoir at 800 K to a cold reservoir at 300 K. Calculate the rate at which the entropy of the two reservoirs changes and determine if the second law is satisfied

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Acacia 4 years 2021-08-28T11:33:52+00:00 1 Answers 341 views 0

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  1. phucdien
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    2021-08-28T11:35:17+00:00
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    Answer:

    0.00417 kW/K or 4.17 W/K

    Second law is satisfied.

    Explanation:

    Parameters given:

    Rate of heat transfer, Q = 2kW

    Temperature of hot reservoir, Th = 800K

    Temperature of cold reservoir, Tc = 300K

    The rate of entropy change is given as:

    ΔS = Q * [(1/Tc) – (1/Th)]

    ΔS = 2 * (1/300 – 1/800)

    ΔS = 2 * 0.002085

    ΔS = 0.00417 kW/K or 4.17 W/K

    Since ΔS is greater than 0, te the second law of thermodynamics is satisfied.

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