A bomb falls with velocity v(t)=C(1−e−kt), where C and k are constants. What is the terminal velocity of the bomb? That is, what is the maxi

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A bomb falls with velocity v(t)=C(1−e−kt), where C and k are constants. What is the terminal velocity of the bomb? That is, what is the maximum valocity the bomb can reach regardless of the height of the bomber?

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Eirian 4 years 2021-08-28T01:05:54+00:00 1 Answers 66 views 0

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  1. Doris
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    2021-08-28T01:07:35+00:00
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    Answer:

    The terminal velocity is equal to C.

    Explanation:

    Making the assumption that k and t are positive, we then have that -kt is negative. The value of e^(-kt) will be equal to 1/(e^(kt))

    If t increases, e^(kt) will increase exponentially and its reciprocal 1/(e^(kt)) will approach zero.

    So, we have:

    v(t) = C*(1-0)

    v(t) = C*(1)

    v(t) = C

    Therefore, C is the terminal velocity.

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