If it requires 7.0 JJ of work to stretch a particular spring by 1.7 cmcm from its equilibrium length, how much more work will be required to

Question

If it requires 7.0 JJ of work to stretch a particular spring by 1.7 cmcm from its equilibrium length, how much more work will be required to stretch it an additional 3.6 cm ?

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Mộc Miên 3 years 2021-08-26T11:17:58+00:00 1 Answers 12 views 0

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  1. mocmien2
    0
    2021-08-26T11:19:31+00:00
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    Answer:

    Explanation:

    First of all, well calculate the spring constant k

    K = 2Ei/x^2

    Where Ei = initial work required

    x = initial stretch length

    k = 2×7/0.017^2 = 48443J/m^2

    Now work done in stretching it to 5.3cm (1.7 + 3.6) or 0.053m

    EF = kx^2/2

    48443 × 0.053^2/2 = 68J

    Work done in stretching additional 3.6cm is equal to

    68J-7J = 61J

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