During a collision that last 3 seconds, an object has its momentum changed by 3 kgm/s. What was the average Force acting on the object (in N

Question

During a collision that last 3 seconds, an object has its momentum changed by 3 kgm/s. What was the average Force acting on the object (in Newtons) during this collision

in progress 0
Mộc Miên 4 years 2021-08-19T09:01:56+00:00 1 Answers 18 views 0

Answers ( )

    0
    2021-08-19T09:03:28+00:00

    Answer:

    F = 1 N

    Explanation:

    Given,

    Change in momentum = 3 kg m/s

    time, t = 3 s

    Force = ?

    We know,

    Force is equal to change in momentum per unit time.

    F = \dfrac{\Delta P}{t}

    F = \dfrac{3}{3}

    F = 1 N

    Hence, average force acting on the object during collision is equal to 1 N.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )