The propeller of a World War II fighter plane is 2.30 m in diameter and spins at 1200 rev/min. What is the centripetal acceleration of the p

Question

The propeller of a World War II fighter plane is 2.30 m in diameter and spins at 1200 rev/min. What is the centripetal acceleration of the propeller tip? Calculate it in meters per second squared and convert to multiples of g.

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Thành Đạt 4 years 2021-08-18T23:58:14+00:00 1 Answers 33 views 0

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  1. MichaelMet
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    2021-08-18T23:59:18+00:00
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    Answer:

    Ac = 36320 m/s^2 = 3702 g

    Explanation:

    First let’s find the linear velocity of the propeller tip.

    The angular velocity is 1200 rev/min, which is 20 rev/s

    One rev is 2*pi radians, so 20 rev/sec = 40*pi rad/s

    To find linear velocity, we multiply the angular velocity by the radius, so:

    V = 40*pi * 2.3 = 92*pi m/s

    The centripetal acceleration is given by Ac = V^2/r, being r the radius. So:

    Ac = (92*pi)^2/2.3 = 36320 m/s^2

    If g is the gravity acceleration = 9.81 m/s^2, we can find Ac in multiples of g by dividing their values:

    Ac = 36320/9.81 = 3702 g

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