A charged belt, 61 cm wide, travels at 43 m/s between a source of charge and a sphere. The belt carries charge into the sphere at a rate cor

Question

A charged belt, 61 cm wide, travels at 43 m/s between a source of charge and a sphere. The belt carries charge into the sphere at a rate corresponding to 100 µA. Compute the surface charge density on the belt.

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Farah 5 years 2021-08-18T04:41:05+00:00 1 Answers 13 views 0

Answers ( )

  1. Dau
    0
    2021-08-18T04:42:26+00:00
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    Answer:

    Surface charge density will be 3.812\times 10^{-6}C/m^2

    Explanation:

    We have given speed of the belt v = 43 m/sec

    Width of the belt w = 61 cm

    We know that charge is equal to Q = It, here Is current and t is time

    And time is equal to i=\frac{L}{v}, here L is distance and v is speed

    Putting the value of t in charge equation

    Q=i\times \frac{L}{v}=\frac{iL}{v}

    Surface charge density is equal to \sigma =\frac{Q}{A}=\frac{iL}{vA}

    We know that width is equal to w=\frac{A}{L}

    So \sigma =\frac{i}{vw}=\frac{100\times 10^{-6}}{43\times 0.61}=3.812\times 10^{-6}C/m^2

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