A jumper cable is used to start a car that has a dead battery. The cable barely reaches the car and is outstretched in a straight line. The

Question

A jumper cable is used to start a car that has a dead battery. The cable barely reaches the car and is outstretched in a straight line. The electric starter motor on the car draws 134 AA . What is the magnetic field at a distance of 0.5 mm from the cable

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Kim Cúc 5 years 2021-08-16T02:21:13+00:00 2 Answers 12 views 0

Answers ( )

  1. thuthuy
    0
    2021-08-16T02:22:14+00:00
    Reply

    Answer:

    2.68\times 10^{-5} T

    Explanation:

    We are given that

    Current,I=134 A

    Distance,r=0.5m

    We have to find the magnetic field at a distance of 0.5 m from the cable.

    We know that magnetic filed ,

    B=\frac{2\mu_0 I}{4\pi r}

    Where \frac{\mu_0}{4\pi}=10^{-7}

    Using the formula

    B=\frac{10^{-7}\times 134}{0.5}

    B=2.68\times 10^{-5} T

    Hence, the magnetic field at a distance 0.5 m from the cable=B=2.68\times 10^{-5} T

  2. RobertKer
    0
    2021-08-16T02:22:41+00:00
    Reply

    Answer:

    Explanation:

    Current in the wire, i = 134 A

    distance, r = 0.5 mm

    The formula for the magnetic field due to straight conductor at a point is

    B = \frac{\mu _{0}}{4\pi }\frac{2i}{r}

    B = 10^{-7}\frac{2\times 134}{0.5\times 10^{-3}}

    B = 0.0536 Tesla

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