A resistor is connected across the terminals of a 9.0-V battery, which delivers 1.5 x 105 J of energy to the resistor in 8.0 hours. What is

Question

A resistor is connected across the terminals of a 9.0-V battery, which delivers 1.5 x 105 J of energy to the resistor in 8.0 hours. What is the resistance of the resistor

in progress 0
Nguyệt Ánh 4 years 2021-08-14T18:33:38+00:00 1 Answers 892 views 0

Answers ( )

  1. yenoanh
    -1
    2021-08-14T18:35:21+00:00
    Reply

    Answer:

    0.2592 Ω

    Explanation:

    From Electric Energy,

    E = V²t/R……………….. Equation 1

    Where E = Electric Energy, V = Voltage, R = Resistance, t = time

    make R the subject of the equation

    R = V²t/E………………… Equation 2

    Given: V = 9.0 V, E = 1.5×10⁵ J, t = 8 hours = 8×60 = 480 s

    Substitute into equation 2

    R = 9²(480)/(1.5×10⁵)

    R = 81×480/150000

    R = 38880/150000

    R = 0.2592 Ω

    Hence the resistance of the resistor = 0.2592 Ω

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )