An object of mass m moves to the right with a speed v. It collides head-on with an object of mass 3m moving with speed v/3 in the opposite d

Question

An object of mass m moves to the right with a speed v. It collides head-on with an object of mass 3m moving with speed v/3 in the opposite direction. If the two objects stick together, what is the speed of the combined object, of mass 4m, after the collision

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Nguyệt Ánh 5 years 2021-08-14T05:16:54+00:00 2 Answers 724 views 1

Answers ( )

  1. Nem
    0
    2021-08-14T05:17:54+00:00
    Reply

    Answer:

    Answer is 0

    Explanation:

    Given the information

    First mass = m

    Second mass = 3m

    Initial velocity = v

    Final velocity = v/3

    The collision occuring here is inelastic and in inelastic collisions the kinetic energy is not conserved however the momentum is conserved.

    According to conservation of momentum initial momentum is equal to final velocity.

    Conservation of momentum is =

    m1v1 + m2v2 = (m1 +m2)vf

    Rearranging the equation to get final velocity we have =>

    mv – 3mv/3 = 4mvf

    vf = 0

  2. thachthao
    0
    2021-08-14T05:18:47+00:00
    Reply

    Answer:

    the answer is 0 m/s

    Explanation:

    This question is describing the law of conservation of momentum

    First object has mass =m

    velocity of first object = v

    second object = 3m

    velocity of second object = v/3

    the law of conservation of momentum is expressed as

    m1V1 – m2V2 = (m1+ m2) V

    substituting the parameters given;

    making V as the subject of formular

    V =\frac{m_{1 } V_{1} -m_{2}V_{2} }{m_{1}+m_{2} }

    V =

    \frac{mV - 3mv/3}{m+ 3m}

    V =\frac{0}{4m}

    = 0 m/s

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