find the coefficient of kinetic friction for a 10 kg box being dragged steadily across the surface with a force of 2.0 Newtons​

Question

find the coefficient of kinetic friction for a 10 kg box being dragged steadily across the surface with a force of 2.0 Newtons​

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Jezebel 5 years 2021-08-11T17:25:58+00:00 1 Answers 22 views 0

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  1. Vodka
    0
    2021-08-11T17:27:30+00:00
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    Answer:

    0.02

    Explanation:

    Force, F=\mu_k N where N is normal reaction and coefficient of kinetic friction is \mu_k. Also, N is equivalent to mg ie N=mg where m is mass of an object and g is acceleration due to gravity. Making \muthe subject of the formula then

    \mu_k=\frac {F}{mg}

    Substituting F with 2 N, m with 10 kg and g with 9.81 then

    \mu_k=\frac {2}{10\times 9.81}=0.0203873598369\approx 0.02

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