A circuit has a 2Ω resistor in series with a 4Ω resistor. What is the total resistance of the circuit?

Question

A circuit has a 2Ω resistor in series with a 4Ω resistor. What is the total resistance of the circuit?

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Adela 5 years 2021-08-10T06:43:24+00:00 1 Answers 20 views 0

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  1. Ben
    0
    2021-08-10T06:45:05+00:00
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    Answer: 6Ω

    Explanation:

    Since the resistors are connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.

    i.e Rtotal = R1 + R2

    R1 = 2Ω

    R2 = 4Ω

    Rtotal = ?

    Rtotal = 2Ω + 4Ω

    Rtotal = 6Ω

    Thus, the total resistance of the circuit is 6Ω

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