Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm .Part AAt a distance from the slits which is

Question

Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm .Part AAt a distance from the slits which is large compared to their separation, what is the phase difference (in radians) in the light from the two slits at an angle of 25.0 ∘ from the centerline?

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Thiên Di 5 years 2021-08-09T21:41:45+00:00 1 Answers 40 views 0

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  1. Orla
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    2021-08-09T21:43:05+00:00
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    Answer:

    The phase difference between waves 31.7 rad

    Explanation:

    Given :

    Wavelength \lambda = 540 \times 10^{-9} m

    Separation between two slit d = 0.370 \times 10^{-3} m

    Angle \theta = 25°

    From the formula of phase difference,

      \delta = \frac{2\pi d }{\lambda} \sin \theta

    Where \delta = phase difference

    \delta = \frac{2 \times \pi \times 0.370 \times 10^{-3} }{540 \times 10^{-9} } \sin 25

    \delta = 31.7 rad

    Therefore, the phase difference between waves 31.7 rad

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