After being struck by a bowling ball, a 1.7 kg bowling pin sliding to the right at 3.8 m/s collides head-on with another 1.7 kg bowling pin

Question

After being struck by a bowling ball, a 1.7 kg bowling pin sliding to the right at 3.8 m/s collides head-on with another 1.7 kg bowling pin initially at rest. Find the final velocity of the second pin in the following situations: a) The first pin moves to the right after the collision at 0.8 m/s. Answer in units of m/s.

in progress 0
Bình An 4 years 2021-08-09T07:07:46+00:00 1 Answers 220 views 0

Answers ( )

  1. Farah
    0
    2021-08-09T07:08:48+00:00
    Reply

    Answer:

    3 m/s

    Explanation:

    Parameters given:

    Mass of first bowling pin, m = 1.7 kg

    Initial velocity of first bowling pin, u = 3.8 m/s

    Final velocity of first bowling pin, v = 0.8 m/s

    Mass of second bowling pin, M = 1.7 kg

    Initial velocity of second bowling pin, U = 0 m/s

    Let the final velocity of the second bowling pin be V

    Using the principle of conservation of momentum:

    Total initial momentum = Total final momentum

    m*u + M*U = m*v + M*V

    (1.7 * 3.8) + 0 = (1.7 * 0.8) + (1.7 * V)

    6.46 = 1.36 + 1.7V

    1.7V = 5.1

    V = 5.1/1.7 = 3 m/s

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )