A very long solenoid of inner radius 4.25 cm creates an oscillating magnetic field B of the form B = B m a x cos ( ω t ) For thi

Question

A very long solenoid of inner radius 4.25 cm creates an oscillating magnetic field B of the form B = B m a x cos ( ω t ) For this solenoid, B max = 0.00275 T and ω = 349 rad/s. What is the maximum value E max of the induced electric field at a perpendicular distance 1.85 cm from the axis of the solenoid?

in progress 0
Nick 4 years 2021-08-09T06:24:10+00:00 1 Answers 18 views 0

Answers ( )

  1. thienthanh
    0
    2021-08-09T06:25:34+00:00
    Reply

    Answer:

    Explanation:

    Flux

    Φ = B A

    = πR²B

    -dΦ / dt = -πR²dB/ dt

    EMF = – πR².00275d.cos ( ω t )/ dt

    EMF = ( πR².00275/ω) sin ω t

    EMFmax = ( πR².00275/ω)

    EMFmax = ∫ E dR , E is elecreic field at distance R from the axis

    = 2πR X E

    ( πR².00275/ω) = 2πR X Emax

    Emax = R x .00275/2ω

    = 1.85 x 10⁻² x .00275 / (2 x 349)

    = .7288 x 10⁻⁷ N/C  

    = 7.288 x 10⁻⁸ N/C

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )