A heavy flywheel rotating counterclockwise about its middle at an original speed of 157.1 rad/s is slowing down because of friction in its b

Question

A heavy flywheel rotating counterclockwise about its middle at an original speed of 157.1 rad/s is slowing down because of friction in its bearings. a. If its acceleration is constant at 1.785 rad/s², find its angular velocity at the end of 1.00 minute. b. The flywheel is 5.50 m in diameter and has a mass of 985 kg. If the flywheel resembles a uniform disk, find the torque applied by friction.

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Latifah 4 years 2021-08-09T06:21:37+00:00 1 Answers 10 views 0

Answers ( )

  1. Ben
    0
    2021-08-09T06:23:10+00:00
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    Answer:

    Part a)

    Final angular speed of the wheel is

    \omega_f = 50 rad/s

    Part b)

    torque on the wheel is given as

    \tau = 6648.3 N m

    Explanation:

    Part a)

    As we know that initial angular speed of the flywheel is

    \omega_i = 157.1 rad/s

    angular deceleration of the flywheel is given as

    \alpha = - 1.785 rad/s^2

    Final angular speed of the fly wheel is given as

    \omega_f = \omega_i + \alpha t

    \omega_f = 157.1 + (-1.785)(60)

    \omega_f = 50 rad/s

    Part b)

    As we know that moment of inertia of the disc is given as

    I = \frac{1}{2}mR^2

    so we have

    I = \frac{1}{2}(985)(\frac{5.50}{2})^2

    I = 3724.5 kg m^2

    So torque on the wheel is given as

    \tau = I \alpha

    \tau = 3724.5(1.785)

    \tau = 6648.3 N m

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