Calculate the absolute value of the magnitude of the impact force on a 60 kg parachutist falling at 10 m/s if the time to stop was 0.7 secon

Question

Calculate the absolute value of the magnitude of the impact force on a 60 kg parachutist falling at 10 m/s if the time to stop was 0.7 seconds.

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Thanh Thu 4 years 2021-08-07T05:43:04+00:00 1 Answers 13 views 0

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  1. sori
    0
    2021-08-07T05:44:18+00:00
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    Answer:

    85.7 N

    Explanation:

    According to Newton’s second law of motion, F is equivalent to the product of mass and acceleration, ma where m is the mass of parachute in kilograms and a is acceleration.

    Acceleration is defined as the rate of change of velocity per unit time hence expressed as

    a=\frac {\triangle v}{t}=\frac {v-u}{t}

    Where v and u represent the final and initial velocities respectively.

    Substituting this into initial equation of f then

    F=m\frac {v-u}{t}

    For this case, the final velocity is zero since it comes ro rest. Substituting 0 m/s dor v and 10 m/s for u then 0.7 s for t we can deduce that

    F=60\times \frac {0-10}{0.7}=−85.71428571428\approx -85.7N

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