A 85 kg lineman tackles a 90 kg receiver. The receiver is running 5.8 m/s, and the lineman is moving 4.1 m/s, at a right angle to the direct

Question

A 85 kg lineman tackles a 90 kg receiver. The receiver is running 5.8 m/s, and the lineman is moving 4.1 m/s, at a right angle to the direction of the receiver’s motion. If the lineman holds on to the receiver while they fall, what is their velocity immediately after the tackle

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Neala 4 years 2021-08-06T18:39:42+00:00 1 Answers 19 views 0

Answers ( )

  1. thachthao
    0
    2021-08-06T18:40:58+00:00
    Reply

    Answer:

    3.59 m/s

    Explanation:

    We are given that

    Mass of lineman,m=85 kg

    Mass of receiver,m’=90 kg

    Speed of receiver,v’=5.8 m/s

    Speed of lineman,v=4.1 m/s

    \theta=90^{\circ}

    We have to find the their velocity immediately after the tackle.

    Initial momentum,P_i=\sqrt{p^2_1+p^2_2}=\sqrt{(85\times 4.1)^2+(90\times 5.8)^2}=627.6 kgm/s

    According to law of conservation of momentum

    Initial momentum=Final momentum=(m+m')V

    627.6=(85+90)V=175V

    V=\frac{627.6}{175}=3.59 m/s

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