The current world-record motorcycle jump is 77.0 m, set by Jason Renie. Assume that he left the take-off ramp at 13.0° to the horizontal and

Question

The current world-record motorcycle jump is 77.0 m, set by Jason Renie. Assume that he left the take-off ramp at 13.0° to the horizontal and that the take-off and landing heights are the same. Neglecting air drag, determine his take-off speed.

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Nem 5 years 2021-08-06T12:20:12+00:00 1 Answers 60 views 0

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    2021-08-06T12:21:47+00:00

    Answer:

    The take-off speed is 41.48 \frac{m}{s}

    Explanation:

    Given :

    Range R = 77 m

    Projectile angle \alpha  = 13°

    From the formula of range,

      R = \frac{v_{o} ^{2}   }{g} \sin 2\alpha

    Find the velocity from above equation,

      v_{o} = \sqrt{\frac{gR}{\sin 2 \alpha } }

      v_{o} = \sqrt{\frac{9.8 \times 77}{\sin 26} }                              ( ∵ g = 9.8 \frac{m}{s^{2} } )

      v_{o} = 41.48 \frac{m}{s}

    Therefore, the take-off speed is 41.48 \frac{m}{s}

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