How many days of a diet of 1910 large calories are equivalent to the gravitational energy change from sea level to the top of Mount Everest,

Question

How many days of a diet of 1910 large calories are equivalent to the gravitational energy change from sea level to the top of Mount Everest, 8848 m above sea level? Assume your mass is 53 kg. (The body is not anywhere near 100% efficient in converting chemical energy into change in altitude. Also note that this is in addition to your basal metabolism.)

in progress 0
Eirian 5 years 2021-08-06T01:57:21+00:00 1 Answers 35 views 0

Answers ( )

  1. Cherry
    0
    2021-08-06T01:58:31+00:00
    Reply

    Answer:

    0.58 days is needed

    Explanation:

    Gravitational energy change from a height change equal to 8848 m for a mass of 53 kg is:

    m*g*h = 53*9.81*8848 = 4600340.64 J = 4600.34 kJ

    4.184 kJ are equivalent to 1 kcal, then:

    4.184 kJ / 4600.34 kJ = 1 kcal / x kcal

    x = 4600.34/4.184

    x = 1099.5 kcal or large calories

    The diet is 1910 kcal/day, then you need 1099.5/1910 = 0.58 days

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )