A recent study found that electrons that have energies between 3.45 eV and 19.9 eV can cause breaks in a DNA molecule even though they do no

Question

A recent study found that electrons that have energies between 3.45 eV and 19.9 eV can cause breaks in a DNA molecule even though they do not ionize the molecule. If a single photon were to transfer its energy to a single electron, what range of light wavelengths could cause DNA breaks?minimum wavelength?

maximum wavelength?

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Xavia 4 years 2021-08-06T00:45:27+00:00 1 Answers 40 views 0

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  1. Dulcie
    0
    2021-08-06T00:46:35+00:00
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    Answer:

    The Minimum wavelength is  \lambda_{min}= 382.2nm

    The Maximum wavelength is \lambda_{max}= 624.2nm

    Explanation:

    From the question we are told that  

                  The energy range is  E_r = 3.25eV \ and \ 19.9eV

       Considering E = 19.9eV

    When a single photon is transferred to to an electron the energy obtained can be calculated as follows

                  E = 19.9eV = 19.9 *1.6 *10^{-19}J

    This energy is mathematically represented as

                        E = \frac{hc}{\lambda_{max}}

    Here h is the Planck’s constant with value of  h= 6.625*10^{-34}J\cdot s

            c is the speed of light with value of  c = 3*10^8 m/s

    Substituting values and making \lambda the subject of the formula

                           \lambda_{max} = \frac{hc}{E}

                             = \frac{6.625*10^{-34} * 3.0*10^{8}}{19.9*1.6*10^{-19}}

                             \lambda_{max}= 624.2nm

      Considering E = 3.25eV

    When a single photon is transferred to to an electron the energy obtained can be calculated as follows

                  E = 19.9eV = 3.25 *1.6 *10^{-19}J

    This energy is mathematically represented as

                        E = \frac{hc}{\lambda_{min}}

    Substituting values and making \lambda the subject of the formula

                           \lambda_{min} = \frac{hc}{E}

                               = \frac{6.625*10^{-34} * 3.0*10^{8}}{3.25*1.6*10^{-19}}

                               \lambda_{min}= 382.2nm

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