A length of copper wire has a resistance 29 Ω. The wire is cut into three pieces of equal length, which are then connected as parallel lengt

Question

A length of copper wire has a resistance 29 Ω. The wire is cut into three pieces of equal length, which are then connected as parallel lengths between points A and B. What resistance will this new “wire” of length L0 3 have between points A and B? Answer in units of Ω.

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Kiệt Gia 4 years 2021-08-05T08:51:30+00:00 1 Answers 23 views 0

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  1. Giakhanh
    0
    2021-08-05T08:52:30+00:00
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    Answer:

    3.222 ohms

    Explanation:

    If the total wire had a resistance of 29 ohms, when cut in three, each piece will have a resistance of 9.666 ohms.

    As these three pieces (R1, R2 and R3) are now connected in parallel, the equivalent resistance R can be calculated using this equation:

    1/R = 1/R1 + 1/R2 + 1/R3

    1/R = 1/9.666 + 1/9.666 + 1/9.666

    1/R = 3/9.666

    R = 9.666/3 = 3.222 ohms

    The resistance between A and B will be 3.222 ohms

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