A 0.245 kg ball is thrown straight up from 2.07 m above the ground. Its initial vertical speed is 8.00 m/s. A short time later, it hits the

Question

A 0.245 kg ball is thrown straight up from 2.07 m above the ground. Its initial vertical speed is 8.00 m/s. A short time later, it hits the ground. Calculate the total work done by the force of gravity during that time.

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Thái Dương 4 years 2021-08-04T23:12:23+00:00 1 Answers 20 views 0

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  1. Vodka
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    2021-08-04T23:13:41+00:00
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    Answer:

    The work done by gravity is 4.975 \: Joules

    Explanation:

    The data given in the question is :

    Mass is 0.245 kg

    Height from ground is 2.07 m

    As we know , the work done is state function , it depends on initial and final position not on the path followed.

    So, work done by gravity = change in potential energy

    Work done = Initial potential energy – final potential energy

    Insert values from question

    Work done = mass \times gravity \times (change \: in \: height)

    Work done = 0.245 kg \times 9.81 m/s^{2} \times 2.07 m

    So, work done = 4.975 Joules

    Hence the work done by gravity is 4.975 \: Joules

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