A circus performer on a pair of stilts exerts a pressure of 32 kPa on the ground. If the performer stands on one stilt, what pressure does t

Question

A circus performer on a pair of stilts exerts a pressure of 32 kPa on the ground. If the performer stands on one stilt, what pressure does the stilt exert on the ground?

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Thành Công 5 years 2021-08-03T23:35:57+00:00 1 Answers 101 views 0

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  1. Maris
    0
    2021-08-03T23:37:03+00:00
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    Answer:

    64 kPa

    Explanation:

    The pressure exerted by a force on a surface is given by

    p=\frac{F}{A}

    where

    p is the pressure

    F is the force

    A is the area on which the force is exerted

    In this problem, let’s call:

    F = the weight of the performer, which is the force

    A = the area of 1 stilt

    At the beginning, the performer is standing on both stilts, so the area on which he exerts pressure is 2A. So the pressure is

    p=\frac{F}{2A}=32 kPa (1)

    Later, he stands on one stilt only. The force exerted is still the same (his weight), however, the area is now reduced to A; therefore, the new pressure is

    p'=\frac{F}{A} = 2(\frac{F}{2A})=2p

    which is twice the value calculated in (1); so, the new pressure is

    p'=2(32)=64 kPa

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